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**PROBLEMS ON AGES**

31) The age of a person is thrice the total ages of his 2 daughters. 0.5 decades hence, his age will be twice of the total ages of his daughters. Then what is the father’s current age?

[0.5 Decades = 5 Years]

A) 35 years

B) 38 years

C) 45 years

D) 48 years

Let, Total of current ages of the 2 daughters is A years.

Then, father’s current age = 3A years.

(3A + 5) = 2 (A +10)

3A + 5 = 2A + 20

A = 15

Therefore, father’s current age = 45 years.

C) 45 Years

32) Sivagami is 2 years elder than Meena. After 6 years the total of their ages will be 7 times of their current age. Then age of Sivagami is :

A) 19 Years

B) 17 years

C) 21 years

D) Data inadequate

Let Meena’s age = A.

Then Sivagami’s age = A + 2

After 6 years the total of their ages will be 7 times of what?

Not clear.

So the given data are inadequate.

D) Data inadequate

33) Pandey got married 0.8 decades ago. His current age is (6/5) times his age at the time of his marriage. Pandey’s brother was ten years younger to him at the time of his marriage. What is the age of Pandey’s Brother?[0.8 decades = 8 years]

A) 38 years

B) 39 years

C) 48 years

D) 58 years

Let Pandey’s current age is A years.

Then, his age at the time of marriage = (A – 8) years

A = (6/5)(A – 8)

5A = 6A – 48

A = 48

Pandey’s sister’s age at the time of his marriage = (A – 8) – 10

= (A – 18) = 30 years.

Pandey’s sister’s current age = (30 + 8) years

= 38 years.

A) 38 Years

34) The ages of X and Y are in the proportion of 6:5 and total of their ages is 44 years. The proportion of their ages after 8 years will be

A) 3 : 6

B) 6 : 3

C) 8 : 7

D) 9 : 5

Let current ages of X and Y correspondingly, is 6A & 5A

Given: 6A + 5A = 44

=> A = 4

Proportion of ages after 0.8 decades will be

6A + 8 : 5A + 8

or, 32:28 or, 8:7

C) 8 : 7

35) The proportion of the ages of father to that of son is 7:3 today. After five years, this rate would be 2:1. How many years old should the father was at the time of son’s birth?

A) 20

B) 22

C) 18

D) 16

Let, Ages of father and Son today is “7A” and “3A” years correspondingly.

Then, 5 years, then we get,

{ (7A + 5)/(3A + 5) }= (2/1)

A = 5

The age of father today is 35 years.

Ages of son’s today is 15 years.

At the time of son’s birth, father have been (35-15) = 20 years.

A) 20 Years

36) Mother is aged thrice than her daughter Rani. After 8 years, he would be 2(1/2) times of Rani’s age. After 8 years, how many times would she be of Rani’s age?

A) 1(1/2) times

B) 2 times

C) 2(1/2) times

D) 4 times

Let Ranis’s current age is A years.

Then, mom’s current age = (A + 3A) years = 4A years.

(4A + 8) = (5/2) (A + 8)

=> 8A + 16 = 5A + 40

=> 3A = 24

A = 8

Needed ratio = { (4A + 16)/(A+16) }

= 48/24

= 2

B) 2 Times

37) The proportion of the ages of Pooja and Karan is 2 : 5, After 8 years, their ages will be in the proportion of 1 : 2. Then what is the variance in their current ages?

A) 24

B) 25

C) 28

D) 30

Let Pooja’s age = 2A

and Karan’s age = 5A

(2A + 8)/(5A+8)= (1/2)

=> 2 (2A + 8) = 5A + 8

=> A = 8

Pooja’s age = 16 years

and Karan’s age = 40 years

variance of their ages = 24 years.

A) 24 Years

38) A year ago the proportion between Sham and Amir’s age was 4:3. 1 year hence the proportion of their ages will be 5:4. The total of their current ages is :

A) 13 years

B) 14 years

C) 16 years

D) None of these

A year ago, Sham’s age = 4A years

And, Amir’s age = 3A years

Current age of Sham = (4A + 1) years

Current age of Amir = (3A + 1) years

1 year hence, Sham’s age = (4A + 2) years

and Amir’s age = (3A + 1) years

So,

{ (4A + 2)/(3A +2) } = 5 /4

=> 16 + 8 = 15A + 10

or, A = 2

Total of their current ages = 4A + 1 + 3A + 1

= 7(A) + 2

= 7(2) + 2 = 16 years.

C) 16 Years

39) A mother said to her daughter, “I was as old as you are at now at the date of your birth.” If the mother’s age is 38 years now, the daughter’s age 5 years back was?

A) 14 years

B) 19 years

C) 23 years

D) 29 years

Daughter’s current age = A years

Then, (38 – A) = A

2A = 38

A = 19 years

Daughter’s age Five years back = (19 – 5) years

= 14 years

A) 14 Years

40) Proportion of Yuvaraj’s age to Ganguly’s age is 4:3. Yuvaraj willl be 26 years old after 6 years. What is the age of Ganguly now?

A) 17 years

B) 15 years

C) 19 years

D) 12 years

Current ages of Yuvaraj = 4A and

Ganguly = 3A

So that 4A + 6 = 26

A = 5

Current age of Ganguly = 3(A)

=> 3 x 5 =15 years

B) 15 Years

41) The ages of Krish and Vaibhav are in the proportion of 3 : 5. After 9 years, the proportion of their ages will be 3 : 4. Then the current age of Vaibhav is:

A) 10

B) 13

C) 15

D) 18

Krish’s age = 3A and

Vaibhav’s age = 5A

{ (3A + 9)/(5A + 9) }=3/4

=> 4 (3A + 9) = 3 (5A + 9)

=> A = 3

Therefore, Vaibhav’s age = 15 years.

C) 15 Years

42) Sajitha’s age is one-sixth of her mother’s age. Sajitha’s mother’s age will be two times of Karthikh’s age after 10 years. If Karthikh’s 8-th birthday was celebrated 2 years before, then what is Sajitha’s current age?

A) 5(1/2) years

B) 12(3/4) years

C) 7 years

D) None of these

Karthikh’s age after 10 years = (8 + 2 + 10) years = 20 years

Sajitha’s mom’s age after 10 years = 40 years.

Sajitha’s mom’s current age = 30 years.

Therefore, Sajitha’s age = (1/6)x 30 years

= 5 years.

D) None of these

43) 5 years ago Amith was three times as old as his daughter and 10 years hence, he will be two times as old as his daughter. Then Amith’s current age is,

A) 55

B) 50

C) 45

D) 40

Amith’s age = A and

daughter’s age =B

Then, A – 5 = 3(B – 5)

=> A – 3B + 10 = 0 ……(1)

And, A + 10 = 2 (A + 10)

=> A – 2B – 10 = 0 ……(2)

Solving the 2 eqns, we will get

A = 50, B = 20.

Therefore,

Amith’s age is 50

And his Daughter’s age is 20

B) 50 Years

44) Aishwarya’s mom was 38 years of age at the time of her birth, while her mom was 36 years old when her 4 years younger sister was born. The variance between the parents ages is :

A) 1 years

B) 3 years

C) 5 years

D) 6 years

Mom’s age when Aishwarya’s sister was born = 36 years.

Dad’s age when Aishwarya’s sister was born = (38 + 4) years = 42 years.

Needed Variance = (42 – 36) years = 6 years.

D) 6 Years

45) A guy was asked to specify his age in years. He said, “Take my age 3 years hence, multiply it by three and subtract thrice of my age 3 years ago and you will know my age.” What was the age of that guy?

A) 16 years

B) 18 years

C) 20 years

D) 22 years

Current age of the guy = A years.

Then, 3 (A + 3) – 3 (A – 3) = A

(3A + 9) – (3A – 9) = A

A = 18

B) 18 Years