General Aptitude questions
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Question 1 
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
A  20 
B  30 
C  33 
D  24 
Question 1 Explanation:
Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = [(0.59x/2x) x 100] % = 30% (approx.)
Question 2 
If A = x% of y and B = y% of x, then which of the following is true?
A  A is smaller than B. 
B  Relationship between A and B cannot be determined. 
C  None of these 
D  If x is smaller than y, then A is greater than B. 
E  A is greater than B 
Question 2 Explanation:
x% of y = [(x/100) (x y)] = [(y/100) (x x)] = y% of x
Therefore A = B.
Question 3 
3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
A  9 
B  12 
C  10 
D  11 
Question 3 Explanation:
Let the required number of working hours per day be x.
More pumps, Less working hours per day (Indirect Proportion)
Less days, More working hours per day (Indirect Proportion)
Pumps 4 : 3
Days 1 : 2
:: 8 : x
Therefor 4 x 1 x x = 3 x 2 x 8
=> x = (3 x 2 x 8)/(4)
=> x = 12.
Question 4 
56, 72, 90, 110, 132, 150
A  72 
B  110 
C  132 
D  150 
Question 4 Explanation:
The numbers are 7 x 8, 8 x 9, 9 x 10, 10 x 11, 11 x 12, 12 x 13.
So, 150 is wrong.
Question 5 
36, 54, 18, 27, 9, 18.5, 4.5
A  18.5 
B  4.5 
C  18 
D  54 
Question 5 Explanation:
The terms are alternatively multiplied by 1.5 and divided by 3. However, 18.5 does not satisfy it.
Question 6 
One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:
A  108 min 
B  144 min 
C  192 min 
D  81 min. 
Question 6 Explanation:
Let the slower pipe alone fill the tank in x minutes.
Then, faster pipe will fill it in x/3 minutes.
=> 4/x = 1/36
=> x = 144 min.
Question 7 
Direction (for Q.No. 6) :
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
6. What is Arun's present age?
I. Five years ago, Arun's age was double that of his son's age at that time.
II. Present ages of Arun and his son are in the ratio of 11 : 6 respectively.
III. Five years hence, the respective ratio of Arun's age and his son's age will become 12 : 7.
A  Only I and II 
B  Any two of the three 
C  Only I and III 
D  None of these 
E  Only II and III 
Question 7 Explanation:
I. 5 years ago, Arun's age = 2 x His son's age.
II. Let the present ages of Arun and his son be 11x and 6x years respectively.
III. 5 years hence, Arun's Age/Son's age = 12/7
Clearly, any two of the above will give Arun's present age.
So Correct answer is (D).
Question 8 
Find the biggest digit that will divide 43, 91 and 183 so as to abandon the same rest in each situation.
A  4 
B  13 
C  7 
D  9

Question 8 Explanation:
Needed number = H.C.F. of (91  43), (183  91) and (183  43)
Question 9 
Direction (for Q.No. 16):
Find the odd man out.
16. 10, 25, 45, 54, 60, 75, 80
A  10 
B  75 
C  54 
D  45 
Question 9 Explanation:
Each of the numbers except 54 is multiple of 5.
Question 10 
A man buys a watch for Rs. 1950 in cash and sells it for Rs. 2200 at a credit of 1 year. If the rate of interest is 10% per annum, the man:
A  gains Rs. 50 
B  gains Rs. 30 
C  loses Rs. 30 
D  gains Rs. 55 
Question 10 Explanation:
S.P.= P.W. of Rs. 2200 due 1 year hence
= Rs.[(2200 x 100)/(100+(10 x 1)]
= Rs. 2000.
Therefore Gain = Rs. (2000  1950) = Rs. 50.
Question 11 
Which of the given fraction is the greatest?
A  63/80 
B  7/8 
C  31/40 
D  13/16 
Question 11 Explanation:
L.C.M. of 8, 16, 40 and 80 = 80.
7/8 = 70/80 ; 13/16 = 65/80 ; 31/40 = 62/80
Since, 70/80 > 65/80 > 63/80 > 62/80
so 7/8 > 13/16 > 63/80 > 31/40
Therefore, 7/8 is the greatest.
Question 12 
Direction (for Q.No. 20):
Insert the missing number.
20. 8, 24, 12, 36, 18, 54, (....)
A  108 
B  27 
C  68 
D  72 
Question 12 Explanation:
Numbers are alternatively multiplied by 3 and divided by 2.
So, the next number = 54 ÷ 2 = 27.
Question 13 
If x = ( 3 + 1) /( 31) and y = ( 3  1)/( 3+1) , then the value of (x² + y²) is:
A  13 
B  14 
C  15 
D  10 
Question 13 Explanation:
x = Sqrt( 3 + 1)/(Sqrt 31) x (Sqrt 3 + 1)/(Sqrt 3+1) = (Sqrt 3 + 1)2 / (Sqrt31) = (Sqrt3 + 1 + 2 3)/2 = 2 + Sqrt3.
Therefore x^2 + y^2 = (2 + 3)^2 + (2  3)^2
= 2(4 + 3)
= 14
Question 14 
If 20% of a = b, then b% of 20 is the same as:
A  5% of a 
B  20% of a 
C  None of these 
D  4% of a 
Question 14 Explanation:
20% of a = b => (20/100) a = b.
= 4% of a.
Question 15 
By investing in 16(2/3)% stock at 64, one earns Rs. 1500. The investment made is:
A  Rs. 9600 
B  Rs. 5760 
C  Rs 7500 
D  Rs. 5640 
Question 15 Explanation:
To earn Rs. 50/3, investment = Rs. 64
To earn Rs. 1500 , investment = Rs. [64 x (3/50) x 1500] = Rs. 5760.
Question 16 
A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was:
A  Rs. 15,000 
B  Rs. 20,000 
C  Rs. 10,000 
D  Rs 2000 
Question 16 Explanation:
Principal = Rs. (100 x 5400 / 12 x 3) = Rs. 15000.
Question 17 
Direction (for Q.Nos. 17  19):
Find out the wrong number in the given sequence of numbers.
17. 582, 605, 588, 611, 634, 617, 600
A  600 
B  605 
C  611 
D  634 
Question 17 Explanation:
Alternatively 23 is added and 17 is subtracted from the terms. So, 634 is wrong.
Question 18 
The very least ideal rectangle, which is divisible by every single of 21, 36 and 66 is:
A  213444 
B  214434 
C  214344 
D  231444 
Question 18 Explanation:
L.C.M. of 21, 36, 66 = 2772.
Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it an ideal rectangle, it must be multiplied by 7 x 11.
So, Needed number = 2^2 x 3^2 x 7^2 x 11^2 = 213444
Question 19 
A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
A  4 
B  5 
C  10 
D  6 
Question 19 Explanation:
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15  x) km/hr.
=> 9x2 = 225
=> x2 = 25
=> x = 5 km/hr.
Question 20 
.009/?= .01
A  .09 
B  .9 
C  .009 
D  9 
Question 20 Explanation:
( .009/? ) = .01;
Then x = (.009/.01)
= .9/1
= .9
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