General Aptitude questions
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Question 1 
The very least ideal rectangle, which is divisible by every single of 21, 36 and 66 is:
A  214344 
B  214434 
C  231444 
D  213444 
Question 1 Explanation:
L.C.M. of 21, 36, 66 = 2772.
Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it an ideal rectangle, it must be multiplied by 7 x 11.
So, Needed number = 2^2 x 3^2 x 7^2 x 11^2 = 213444
Question 2 
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
A  30 
B  33 
C  24 
D  20 
Question 2 Explanation:
Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = [(0.59x/2x) x 100] % = 30% (approx.)
Question 3 
If x = ( 3 + 1) /( 31) and y = ( 3  1)/( 3+1) , then the value of (x² + y²) is:
A  10 
B  14 
C  15 
D  13 
Question 3 Explanation:
x = Sqrt( 3 + 1)/(Sqrt 31) x (Sqrt 3 + 1)/(Sqrt 3+1) = (Sqrt 3 + 1)2 / (Sqrt31) = (Sqrt3 + 1 + 2 3)/2 = 2 + Sqrt3.
Therefore x^2 + y^2 = (2 + 3)^2 + (2  3)^2
= 2(4 + 3)
= 14
Question 4 
3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
A  11 
B  12 
C  10 
D  9 
Question 4 Explanation:
Let the required number of working hours per day be x.
More pumps, Less working hours per day (Indirect Proportion)
Less days, More working hours per day (Indirect Proportion)
Pumps 4 : 3
Days 1 : 2
:: 8 : x
Therefor 4 x 1 x x = 3 x 2 x 8
=> x = (3 x 2 x 8)/(4)
=> x = 12.
Question 5 
A man buys a watch for Rs. 1950 in cash and sells it for Rs. 2200 at a credit of 1 year. If the rate of interest is 10% per annum, the man:
A  gains Rs. 50 
B  gains Rs. 55 
C  gains Rs. 30 
D  loses Rs. 30 
Question 5 Explanation:
S.P.= P.W. of Rs. 2200 due 1 year hence
= Rs.[(2200 x 100)/(100+(10 x 1)]
= Rs. 2000.
Therefore Gain = Rs. (2000  1950) = Rs. 50.
Question 6 
A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was:
A  Rs. 10,000 
B  Rs. 20,000 
C  Rs. 15,000 
D  Rs 2000 
Question 6 Explanation:
Principal = Rs. (100 x 5400 / 12 x 3) = Rs. 15000.
Question 7 
Direction (for Q.No. 6) :
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
6. What is Arun's present age?
I. Five years ago, Arun's age was double that of his son's age at that time.
II. Present ages of Arun and his son are in the ratio of 11 : 6 respectively.
III. Five years hence, the respective ratio of Arun's age and his son's age will become 12 : 7.
A  Any two of the three 
B  Only II and III 
C  Only I and III 
D  Only I and II 
E  None of these 
Question 7 Explanation:
I. 5 years ago, Arun's age = 2 x His son's age.
II. Let the present ages of Arun and his son be 11x and 6x years respectively.
III. 5 years hence, Arun's Age/Son's age = 12/7
Clearly, any two of the above will give Arun's present age.
So Correct answer is (D).
Question 8 
Direction (for Q.No. 16):
Find the odd man out.
16. 10, 25, 45, 54, 60, 75, 80
A  45 
B  10 
C  75 
D  54 
Question 8 Explanation:
Each of the numbers except 54 is multiple of 5.
Question 9 
If A = x% of y and B = y% of x, then which of the following is true?
A  A is smaller than B. 
B  Relationship between A and B cannot be determined. 
C  None of these 
D  A is greater than B 
E  If x is smaller than y, then A is greater than B. 
Question 9 Explanation:
x% of y = [(x/100) (x y)] = [(y/100) (x x)] = y% of x
Therefore A = B.
Question 10 
One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:
A  192 min 
B  108 min 
C  144 min 
D  81 min. 
Question 10 Explanation:
Let the slower pipe alone fill the tank in x minutes.
Then, faster pipe will fill it in x/3 minutes.
=> 4/x = 1/36
=> x = 144 min.
Question 11 
.009/?= .01
A  9 
B  .9 
C  .09 
D  .009 
Question 11 Explanation:
( .009/? ) = .01;
Then x = (.009/.01)
= .9/1
= .9
Question 12 
A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
A  4 
B  5 
C  10 
D  6 
Question 12 Explanation:
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15  x) km/hr.
=> 9x2 = 225
=> x2 = 25
=> x = 5 km/hr.
Question 13 
36, 54, 18, 27, 9, 18.5, 4.5
A  4.5 
B  18 
C  18.5 
D  54 
Question 13 Explanation:
The terms are alternatively multiplied by 1.5 and divided by 3. However, 18.5 does not satisfy it.
Question 14 
By investing in 16(2/3)% stock at 64, one earns Rs. 1500. The investment made is:
A  Rs. 5760 
B  Rs. 5640 
C  Rs. 9600 
D  Rs 7500 
Question 14 Explanation:
To earn Rs. 50/3, investment = Rs. 64
To earn Rs. 1500 , investment = Rs. [64 x (3/50) x 1500] = Rs. 5760.
Question 15 
Which of the given fraction is the greatest?
A  7/8 
B  13/16 
C  31/40 
D  63/80 
Question 15 Explanation:
L.C.M. of 8, 16, 40 and 80 = 80.
7/8 = 70/80 ; 13/16 = 65/80 ; 31/40 = 62/80
Since, 70/80 > 65/80 > 63/80 > 62/80
so 7/8 > 13/16 > 63/80 > 31/40
Therefore, 7/8 is the greatest.
Question 16 
Find the biggest digit that will divide 43, 91 and 183 so as to abandon the same rest in each situation.
A  13 
B  4 
C  7 
D  9

Question 16 Explanation:
Needed number = H.C.F. of (91  43), (183  91) and (183  43)
Question 17 
If 20% of a = b, then b% of 20 is the same as:
A  4% of a 
B  20% of a 
C  None of these 
D  5% of a 
Question 17 Explanation:
20% of a = b => (20/100) a = b.
= 4% of a.
Question 18 
Direction (for Q.No. 20):
Insert the missing number.
20. 8, 24, 12, 36, 18, 54, (....)
A  27 
B  108 
C  68 
D  72 
Question 18 Explanation:
Numbers are alternatively multiplied by 3 and divided by 2.
So, the next number = 54 ÷ 2 = 27.
Question 19 
56, 72, 90, 110, 132, 150
A  110 
B  132 
C  72 
D  150 
Question 19 Explanation:
The numbers are 7 x 8, 8 x 9, 9 x 10, 10 x 11, 11 x 12, 12 x 13.
So, 150 is wrong.
Question 20 
Direction (for Q.Nos. 17  19):
Find out the wrong number in the given sequence of numbers.
17. 582, 605, 588, 611, 634, 617, 600
A  611 
B  634 
C  600 
D  605 
Question 20 Explanation:
Alternatively 23 is added and 17 is subtracted from the terms. So, 634 is wrong.
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