General Aptitude questions
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Question 1 
36, 54, 18, 27, 9, 18.5, 4.5
A  18 
B  18.5 
C  4.5 
D  54 
Question 1 Explanation:
The terms are alternatively multiplied by 1.5 and divided by 3. However, 18.5 does not satisfy it.
Question 2 
A man walked diagonally across a square lot. Approximately, what was the percent saved by not walking along the edges?
A  30 
B  20 
C  24 
D  33 
Question 2 Explanation:
Let the side of the square(ABCD) be x metres.
Then, AB + BC = 2x metres.
AC = 2x = (1.41x) m.
Saving on 2x metres = (0.59x) m.
Saving % = [(0.59x/2x) x 100] % = 30% (approx.)
Question 3 
By investing in 16(2/3)% stock at 64, one earns Rs. 1500. The investment made is:
A  Rs. 5640 
B  Rs 7500 
C  Rs. 5760 
D  Rs. 9600 
Question 3 Explanation:
To earn Rs. 50/3, investment = Rs. 64
To earn Rs. 1500 , investment = Rs. [64 x (3/50) x 1500] = Rs. 5760.
Question 4 
If A = x% of y and B = y% of x, then which of the following is true?
A  Relationship between A and B cannot be determined. 
B  A is smaller than B. 
C  None of these 
D  A is greater than B 
E  If x is smaller than y, then A is greater than B. 
Question 4 Explanation:
x% of y = [(x/100) (x y)] = [(y/100) (x x)] = y% of x
Therefore A = B.
Question 5 
Find the biggest digit that will divide 43, 91 and 183 so as to abandon the same rest in each situation.
A  9

B  4 
C  7 
D  13 
Question 5 Explanation:
Needed number = H.C.F. of (91  43), (183  91) and (183  43)
Question 6 
Direction (for Q.No. 16):
Find the odd man out.
16. 10, 25, 45, 54, 60, 75, 80
A  10 
B  54 
C  75 
D  45 
Question 6 Explanation:
Each of the numbers except 54 is multiple of 5.
Question 7 
Which of the given fraction is the greatest?
A  31/40 
B  7/8 
C  13/16 
D  63/80 
Question 7 Explanation:
L.C.M. of 8, 16, 40 and 80 = 80.
7/8 = 70/80 ; 13/16 = 65/80 ; 31/40 = 62/80
Since, 70/80 > 65/80 > 63/80 > 62/80
so 7/8 > 13/16 > 63/80 > 31/40
Therefore, 7/8 is the greatest.
Question 8 
The very least ideal rectangle, which is divisible by every single of 21, 36 and 66 is:
A  213444 
B  214434 
C  231444 
D  214344 
Question 8 Explanation:
L.C.M. of 21, 36, 66 = 2772.
Now, 2772 = 2 x 2 x 3 x 3 x 7 x 11
To make it an ideal rectangle, it must be multiplied by 7 x 11.
So, Needed number = 2^2 x 3^2 x 7^2 x 11^2 = 213444
Question 9 
3 pumps, working 8 hours a day, can empty a tank in 2 days. How many hours a day must 4 pumps work to empty the tank in 1 day?
A  10 
B  11 
C  12 
D  9 
Question 9 Explanation:
Let the required number of working hours per day be x.
More pumps, Less working hours per day (Indirect Proportion)
Less days, More working hours per day (Indirect Proportion)
Pumps 4 : 3
Days 1 : 2
:: 8 : x
Therefor 4 x 1 x x = 3 x 2 x 8
=> x = (3 x 2 x 8)/(4)
=> x = 12.
Question 10 
A man buys a watch for Rs. 1950 in cash and sells it for Rs. 2200 at a credit of 1 year. If the rate of interest is 10% per annum, the man:
A  gains Rs. 50 
B  gains Rs. 30 
C  gains Rs. 55 
D  loses Rs. 30 
Question 10 Explanation:
S.P.= P.W. of Rs. 2200 due 1 year hence
= Rs.[(2200 x 100)/(100+(10 x 1)]
= Rs. 2000.
Therefore Gain = Rs. (2000  1950) = Rs. 50.
Question 11 
Direction (for Q.Nos. 17  19):
Find out the wrong number in the given sequence of numbers.
17. 582, 605, 588, 611, 634, 617, 600
A  634 
B  600 
C  605 
D  611 
Question 11 Explanation:
Alternatively 23 is added and 17 is subtracted from the terms. So, 634 is wrong.
Question 12 
If x = ( 3 + 1) /( 31) and y = ( 3  1)/( 3+1) , then the value of (x² + y²) is:
A  13 
B  15 
C  10 
D  14 
Question 12 Explanation:
x = Sqrt( 3 + 1)/(Sqrt 31) x (Sqrt 3 + 1)/(Sqrt 3+1) = (Sqrt 3 + 1)2 / (Sqrt31) = (Sqrt3 + 1 + 2 3)/2 = 2 + Sqrt3.
Therefore x^2 + y^2 = (2 + 3)^2 + (2  3)^2
= 2(4 + 3)
= 14
Question 13 
56, 72, 90, 110, 132, 150
A  150 
B  110 
C  72 
D  132 
Question 13 Explanation:
The numbers are 7 x 8, 8 x 9, 9 x 10, 10 x 11, 11 x 12, 12 x 13.
So, 150 is wrong.
Question 14 
A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and comes back in a total of 4 hours 30 minutes. The speed of the stream (in km/hr) is:
A  10 
B  6 
C  5 
D  4 
Question 14 Explanation:
Let the speed of the stream be x km/hr. Then,
Speed downstream = (15 + x) km/hr,
Speed upstream = (15  x) km/hr.
=> 9x2 = 225
=> x2 = 25
=> x = 5 km/hr.
Question 15 
.009/?= .01
A  .09 
B  9 
C  .9 
D  .009 
Question 15 Explanation:
( .009/? ) = .01;
Then x = (.009/.01)
= .9/1
= .9
Question 16 
Direction (for Q.No. 20):
Insert the missing number.
20. 8, 24, 12, 36, 18, 54, (....)
A  72 
B  27 
C  68 
D  108 
Question 16 Explanation:
Numbers are alternatively multiplied by 3 and divided by 2.
So, the next number = 54 ÷ 2 = 27.
Question 17 
One pipe can fill a tank three times as fast as another pipe. If together the two pipes can fill the tank in 36 minutes, then the slower pipe alone will be able to fill the tank in:
A  192 min 
B  108 min 
C  81 min. 
D  144 min 
Question 17 Explanation:
Let the slower pipe alone fill the tank in x minutes.
Then, faster pipe will fill it in x/3 minutes.
=> 4/x = 1/36
=> x = 144 min.
Question 18 
A man took loan from a bank at the rate of 12% p.a. simple interest. After 3 years he had to pay Rs. 5400 interest only for the period. The principal amount borrowed by him was:
A  Rs 2000 
B  Rs. 10,000 
C  Rs. 20,000 
D  Rs. 15,000 
Question 18 Explanation:
Principal = Rs. (100 x 5400 / 12 x 3) = Rs. 15000.
Question 19 
If 20% of a = b, then b% of 20 is the same as:
A  5% of a 
B  20% of a 
C  4% of a 
D  None of these 
Question 19 Explanation:
20% of a = b => (20/100) a = b.
= 4% of a.
Question 20 
Direction (for Q.No. 6) :
Each of the questions given below consists of a question followed by three statements. You have to study the question and the statements and decide which of the statement(s) is/are necessary to answer the question.
6. What is Arun's present age?
I. Five years ago, Arun's age was double that of his son's age at that time.
II. Present ages of Arun and his son are in the ratio of 11 : 6 respectively.
III. Five years hence, the respective ratio of Arun's age and his son's age will become 12 : 7.
A  Only I and III 
B  Any two of the three 
C  Only II and III 
D  None of these 
E  Only I and II 
Question 20 Explanation:
I. 5 years ago, Arun's age = 2 x His son's age.
II. Let the present ages of Arun and his son be 11x and 6x years respectively.
III. 5 years hence, Arun's Age/Son's age = 12/7
Clearly, any two of the above will give Arun's present age.
So Correct answer is (D).
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