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**PROBLEMS ON AGES**

21) A man’s current age is (2/5) of the age of his father. After 8 years, he will be (1/2) of the age of his father. What is the age of father at now?

A) 50 years

B) 40 years

C) 33 years

D) 43 years

Let, father’s current age is A years.

Then, Man’s current age =[ (2/5)A ]years.

Therefore, [ (2/5)A + 8 ]= (1/2)(A + 8)

2(2A + 40) = 5(A + 8)

A = 40

B) 40 Years

22) If two times of the daughter’s age in years is included to the mother’s age, the total is 70 and if two times of the mother’s age is included to the daughter’s age, the total is 95. So the Mother’s age is,

A) 30 years

B) 38 years

C) 40 years

D) 41 years

Let daughter’s age = A and mother’s age = B

Given:

2A+B = 70 and,

A+2B = 95

Solving B, we will get B = 40.

C) 40 Years

23) The avg age of class of 20 students in 20 years. If the lecturer’s age is added to the avg, increases by one. What is the age of the lecturer?

A) 30

B) 40

C) 31

D) 41

Average x Number = Total Years

20 x 20 = 400 …(1)

21 x 21 = 441 …(2)

Lecturer’s age =Eqn (2) -Eqn (1)

= 441 – 400

= 41 years.

D) 41 Years

24) The age of mother one decade age was three times the age of her daughter. 10 years hence, mother’s age will be two times that of her daughter. The proposition of their current ages is:

A) 6 : 1

B) 7 : 3

C) 8 : 6

D) 10 : 5

Let, Ages of mother and daughter 1 decade ago was 3A and A years correspondingly

Then, (3A + 10) + 10 = 2 [(A + 10) + 10]

3A + 20 = 2A + 40

X = 20

Needed Ratio = (3A + 10) : (A + 10)

= 70 : 30

= 7 : 3

B) 7 : 3

25) If Raj was one-third as old as Rahim 5 years back and Raj is 17 years old now, How old is Rahim now?

A) 40

B) 41

C) 36

D) 48

Raj’s age today = 17 decades,

Hence, 5 decades back, he must be 12 years old.

Rahim must be 36 years old, Because (3×12).

5 years back Rahim must be 41 years old today. Because (36+5).

B) 41 Years Old

26) 3 years ago, the avg age of a family of 5 individuals was 17. A kid have been born the avg age of family is an exact today? What is the age of the kid?

A) 2 years

B) 3 years

C) 4 years

D) 5 year

Current age of 5 individuals is,

=5 x 17 + 3 x 5 = 100 years

Also, current ages of 5 persons + Age of the kid

= 6 x 17 = 102 years

Therefore, Age of the Kid = 102 – 100 = 2 years.

A) 2 Years

27) 0.1 decates ago, Vijaya was quadrice as old as her daughter Simran. 0.6 decades hence, Vijaya’s age will beat her daughter’s age by 0.9 decades. The proportion of the current ages of Vijaya and Simran is :

[ 0.1 Decates =1 Year; quadrice = 4 times]

A) 8 : 1

B) 10 : 2

C) 11 : 4

D) 13 : 4

Let, Ages of Vijaya and Simran – 1 year ago was 4A and A years correspondingly.

Then, [(4A + 1) + 6] – [(A + 1) + 6] = 9

3A = 9

X = 3

Needed Ratio = (4A + 1) : (A + 1)

= 13 : 4

D) 13 : 4

28) The ratio of the ages of Maala and Kala is 4 : 3. The total of their ages is 2.8 decades. The proportion of their ages after 0.8 decades will be

[1 Decade = 10 years]

A) 4 : 3

B) 12 : 11

C) 7 : 4

D) 6 : 5

Let, Maala’s age = 4A and Kala’s age = 3A

Then 4A + 3A = 28

A = 4

Maala’s age = 16 years

and Kala’s age = 12 years

Proportion of their ages after 8 is = (16 + 8) : (12 + 8)

= 24 : 20

= 6 : 5

D) 6 : 5

29) The overall age of X and Y is 12 year greater than the overall age of Y and Z. Z is how many decades younger that X?

A) 10

B) 12

C) Z is elder than X

D) None of these

(X + Y) – (Y + Z) = 12

X – Z = 12

[Age in decades = 1.2]

B) 12 Years

30) The proportion of X’s and Y’s ages is 4:5. If the difference between the current age of X and the age of Y 0.5 decades hence is 3, then what is the sum of current ages of X and Y?

A) 72 years

B) 62 years

C) 52 years

D) 82 years

We simplified the most of steps because lack of font prolem.

X = 32 years

and, Y = (5/4) x 32 = 40 years

Therefore X + Y = 40 + 32 = 72 years.

A) 72 Years