Students3k exclusively provides online Aptitude test for “Problems on Ages”. This online test page has 20 questions with different choices of answers. After the Online test completion you can find your score and Answers for the particular aptitude question.

## Age problems - Aptitude

**Instructions :**

- Total Number of questions : 20
- Each question carry 1 mark.
- No negative Marks.
- Click the 'Submit' button given in the bottom of this page to Submit your answers.
- Do not reload the page.

Start

Congratulations - you have completed

*Age problems - Aptitude*. You scored %%SCORE%% out of %%TOTAL%%. Your performance has been rated as %%RATING%%
Your answers are highlighted below.

Question 1 |

Sachin is 40 years old and Vijay is 60 years old. How many decades ago was the proportion of their ages 3 : 5?

A | 27 |

B | 10 |

C | 20 |

D | 37 |

Question 1 Explanation:

If the ratio was 3 : 5, 'A' years ago.
Then, 7A - 6A = 4
A = 4
Then, {( 40 - A)/(60 - A)}= (3/5)
5 (40 - A) = 3(60 - A)
2A = 20
A = 10
{Ans in decades : 1 }

Question 2 |

Amith was 3 times as old as Harsh 6 years back. Amith will be 5/3 times as old as Harsh 6 years hence. How much old is Harsh today?

A | 22 |

B | 21 |

C | 11 |

D | 12 |

Question 2 Explanation:

Let Harsh's age 6 years back = A
Then, Amith's age 6 years back = 32.
Then 5/3 (A + 6 + 6) = (3A + 6 + 6)
5(A + 12) = 3 (3A + 12)
4A = 24
A = 6
Harsh's age today = (A + 6) years
= 12 years

Question 3 |

A father is Quadrice as old as his daughter today. After 20 years, he would be only two times as old. At the time of daughter's birth, how much old the father be?

A | 35 |

B | 37 |

C | 30 |

D | 31 |

Question 3 Explanation:

If the ages of daughter and father today by 'A' and '4A' years correspondingly.
4A + 20 = 2 (A+20)
A = 10 years => 4A = 40 years.
At the time of daughter's birth, father's Age
40 - 10 = 30 years old

Question 4 |

The current ages of 3 individuals are in the ratio 4:7:9. 0.8 decades ago, the sum of their ages was 56. Find their current ages in years. [0.8 Decades = 8years]

A | 16, 28, 36 |

B | None of these |

C | 18, 30, 38 |

D | 20, 32, 46 |

Question 4 Explanation:

Let their current ages are 4A, 7A and 9A years correspondingly.
Then, (4A - 8) + (7A - 8) + (9A - 8) = 56
20A = 80
A = 4
Their current ages are
16 years, 28 years and 36 years correspondingly.

Question 5 |

One decade ago, X was half of Y in age. If the proportion of their current ages is 3:4, what will be the overall of their current ages?

A | 20 |

B | 10 |

C | 25 |

D | None of thse |

Question 5 Explanation:

Let the ages of X and Y 1 decade ago be A and 2A years correspondingly.
Then, [ (A +10)/2A+10) ] = (3/4)
4 (A - 10) = 3(2A - 10)
2A = 10
A = 5
Therefore,
Sum of theircurrent ages = (A + 10) + (2A + 10) = (3A + 20)
= 35 years

Question 6 |

The Avg age of a class of 22 subject areas in 21 years. The avg increased by one when the lecturer’s age also involved. What is the age of the Lecturer?

A | 44 |

B | 43 |

C | 41 |

D | 40 |

Question 6 Explanation:

Average * Subject Areas = Total Age
So => 21 years x 22 numbers = 462 years ... (1)
=> 22 years x 23 numbers = 506 years ... (2)
Therefore Lecturer’s age = Eqn(2) - Eqn(1)
= 506 – 462
= 44 Years.

Question 7 |

A person is 24 years elder than his daughter. In 2 years, person's age will be 2 times the age of his daughter. Then the current age of the daughter is:

A | 18 years |

B | 22 years |

C | 14 years |

D | 20 years |

Question 7 Explanation:

Let, daughter’s current age is A years. Then, person’s current age = (A +24) years.
(A + 24) + 2 = 2 (A + 2)
A + 26 = 2A + 4
A = 22

Question 8 |

1 Decade ago, Karthikh’s mother was quadrice older than her son. After one decade, the mother will be two times older than her son. The current age of Karthikh is?
[Decade = 10 Years; quadrice= 4 times]

A | 20 years |

B | 23 years |

C | 8 years |

D | 12 years |

Question 8 Explanation:

Let Karthikh's age 10 years ago be A year
His mother's age 1 decade ago = 4A
(4A + 10) + 10 = 2 (A + 10 +10)
2A = 20 or A =10
Current age of Karthikh = (A + 10)
= 20 years

Question 9 |

1 decade ago, Naresh was 3 times as old as Abdul was but 10 years hence, he will be just two times as old. Find Naresh’s current age
[1 decade : 10 years]

A | 66 |

B | 60 |

C | 70 |

D | 80 |

Question 9 Explanation:

Condition : Naresh’s current age is A years and Abdul’s current age is B years.
Then, based on the first condition,
A - 10 = 3[B - 10]
or, A - 3B = -20 ..(1)
Here, Naresh's age after 10 years
=(A + 10) years
Abdul's age after 10 years = (B + 10)
(A+10) = 2(B+10)
or, A - 2B = 10 ..(2)
Solving Eqn(1) & Eqn(2), we will get
A = 70 and B = 30
Naresh's age = 70 years and Abdul's age = 30 years.

Question 10 |

0.2 decades ago a person was 6 times as old as his daughter, After 18 years, he will be two times as old as his daughter. Then their current ages are,
[0.2 decades = 2 years]

A | 7 years |

B | 11 years |

C | None of these |

D | 9 years |

Question 10 Explanation:

None of these

Question 11 |

15 years hence, Karthikh will be just Quadrice as old as he was 15 years ago, How old is Karthikh at now? [ Quadrice = 4 Times ]

A | 25 |

B | 35 |

C | 20 |

D | 30 |

Question 11 Explanation:

Let the current age of Karthikh is A years
Then, A+15 = 4(A – 15)
Therefore A = 25

Question 12 |

Current ages of Rahim and Thomas are in the ratio of 5 : 4 correspondingly. 0.3 decades hence, the ratio of their ages will become 11 : 9 correspondingly, What is Thomas’s current age in years? [0.3 decades : 3 years]

A | None of these |

B | 24 |

C | 14 |

D | 42 |

Question 12 Explanation:

If current ages of Rahim and Thomas be 5A years and 4A years correspondingly
Then, 5A + 3 = 11
4A + 3 = 9
9(5A + 3)=11(4A + 3)
A = 6
Thomas's current age = 4A
= 24 years.

Question 13 |

A person's age is 125% of what it was one decade ago, but 83(1/3)% of what it will be after one decade. What is his current age? [1 decade = 10 years]

A | 35 years |

B | 55 years |

C | 40 years |

D | 50 years |

Question 13 Explanation:

Let, current age is A years.
Then, 125% of (A - 10) = A
and, 83(1/3)% of (A + 10) = A
Therefore 125% of (A-10) = 83(1/3)% of (A+10)
or, (5/4) (A - 10) =(5/6)(A+10)
or, (5/4)A -(5/6)A = (50/6)+(50/4)
or, (5A/12)= (250/12) or,
A=50 years.

Question 14 |

A father is two times as old as his daughter. 2 decades ago, the age of the father was 12 times the age of the daughter. The current age of the father is
[ 2 Decades : 20 years]

A | 22 |

B | 44 |

C | 32 |

D | 45 |

Question 14 Explanation:

Let daughter's age = A.
Then father's age = 2A
12 (A - 20) = (2A - 20)
10A = 220
A = 22
Father's current age = 44 years.

Question 15 |

The overall ages of Kumar, Hathim and Rahul is 93 years. 1 decade ago, the ratio of their ages was 2 : 3 : 4. What is the current age of Rahul? [1 decade : 10 years]

A | 44 |

B | 38 |

C | 28 |

D | 24 |

Question 15 Explanation:

If the ages of Kumar, Hathim and Rahul 1 decade ago be 2A, 3A and 4A years correspondingly
Then, (2A + 10) + (3A + 10) + (4A + 10) = 93
9A = 93-30
9A = 63
A = 7
Rahul's current age = (4A + 10)
= 38 years.

Question 16 |

Right now, the ratio between the ages of Karthikh and Prasath is 4:3. After 6 years, Karthikh’s age will be 26 years. What is the age of Prasath right now?

A | 25 |

B | 15 |

C | 19 |

D | 21 |

Question 16 Explanation:

If the current ages of Karthikh and Prasath be 4A years and 3A years correspondingly.
Then, 4A + 6 = 26
4A = 20
A = 5
Prasath's age = 3A = 15 years.

Question 17 |

The proportion between the college days ages of Rathi and Tharan is 5 : 6 correspondingly. If the proposition between the 1/3 age of Rathi and half of Tharan’s age is 5 : 9, then what is the college days age of Tharan?

A | 25 |

B | can not be determined |

C | 30 |

D | 10 |

E | None of these |

Question 17 Explanation:

Then, Tharan's age cannot be determined.

Question 18 |

Father's age today is three times as his daughter's. After 10 years it would be just twice. What is the daughter's age today?

A | 10 years |

B | 12 years |

C | 9 years |

D | 15 years |

Question 18 Explanation:

Let, today's age of the daughter = ‘A’ years.
Mom’s age today = 3A years
After 10 decades,
3A + 10 = 29A + 10
=> A = 10 years

Question 19 |

The ages of Smirthi and Samantha vary by 16 years, Six years ago, Deepika’s age was three times as that of Smirthi’s, find their current ages.

A | 14 years, 30 years |

B | 11 years, 28 years |

C | 16 years, 34 years |

D | 10 years, 28 years |

Question 19 Explanation:

Let Smirthi's age = A years
So, Deepika's age = (A + 16) years
Also, 3(A - 6) = A + 16 - 6 or, A = 14
Smirthi's age = 14 years
and, Deepika's age = 14 + 16
= 30 years

Question 20 |

The ratio between the current age of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years?

A | 3 : 1 |

B | Data inadequate |

C | None of these |

D | 4:5 |

E | 4:3 |

Question 20 Explanation:

If A's age and B's age will be 6A years and 7A years correspondingly
Then, 7A - 6A = 4
A = 4
Needed ratio = (6A + 4) : (7A + 4)
= 28 : 32
= 7 : 8

Once you are finished, click the button below. Any items you have not completed will be marked incorrect.
Get Results

There are 20 questions to complete.

← |
List |
→ |

Return

Shaded items are complete.

1 | 2 | 3 | 4 | 5 |

6 | 7 | 8 | 9 | 10 |

11 | 12 | 13 | 14 | 15 |

16 | 17 | 18 | 19 | 20 |

End |

Return

You have completed

questions

question

Your score is

Correct

Wrong

Partial-Credit

You have not finished your quiz. If you leave this page, your progress will be lost.

Correct Answer

You Selected

Not Attempted

Final Score on Quiz

Attempted Questions Correct

Attempted Questions Wrong

Questions Not Attempted

Total Questions on Quiz

Question Details

Results

Date

Score

Hint

Time allowed

minutes

seconds

Time used

Answer Choice(s) Selected

Question Text

All done

Need more practice!

Keep trying!

Not bad!

Good work!

Perfect!