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## Age problems - Aptitude

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- Total Number of questions : 20
- Each question carry 1 mark.
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Question 1 |

Father's age today is three times as his daughter's. After 10 years it would be just twice. What is the daughter's age today?

A | 10 years |

B | 12 years |

C | 9 years |

D | 15 years |

Question 1 Explanation:

Let, today's age of the daughter = ‘A’ years.
Mom’s age today = 3A years
After 10 decades,
3A + 10 = 29A + 10
=> A = 10 years

Question 2 |

The overall ages of Kumar, Hathim and Rahul is 93 years. 1 decade ago, the ratio of their ages was 2 : 3 : 4. What is the current age of Rahul? [1 decade : 10 years]

A | 28 |

B | 44 |

C | 24 |

D | 38 |

Question 2 Explanation:

If the ages of Kumar, Hathim and Rahul 1 decade ago be 2A, 3A and 4A years correspondingly
Then, (2A + 10) + (3A + 10) + (4A + 10) = 93
9A = 93-30
9A = 63
A = 7
Rahul's current age = (4A + 10)
= 38 years.

Question 3 |

The proportion between the college days ages of Rathi and Tharan is 5 : 6 correspondingly. If the proposition between the 1/3 age of Rathi and half of Tharan’s age is 5 : 9, then what is the college days age of Tharan?

A | 25 |

B | None of these |

C | can not be determined |

D | 10 |

E | 30 |

Question 3 Explanation:

Then, Tharan's age cannot be determined.

Question 4 |

A person is 24 years elder than his daughter. In 2 years, person's age will be 2 times the age of his daughter. Then the current age of the daughter is:

A | 14 years |

B | 22 years |

C | 20 years |

D | 18 years |

Question 4 Explanation:

Let, daughter’s current age is A years. Then, person’s current age = (A +24) years.
(A + 24) + 2 = 2 (A + 2)
A + 26 = 2A + 4
A = 22

Question 5 |

1 decade ago, Naresh was 3 times as old as Abdul was but 10 years hence, he will be just two times as old. Find Naresh’s current age
[1 decade : 10 years]

A | 60 |

B | 66 |

C | 70 |

D | 80 |

Question 5 Explanation:

Condition : Naresh’s current age is A years and Abdul’s current age is B years.
Then, based on the first condition,
A - 10 = 3[B - 10]
or, A - 3B = -20 ..(1)
Here, Naresh's age after 10 years
=(A + 10) years
Abdul's age after 10 years = (B + 10)
(A+10) = 2(B+10)
or, A - 2B = 10 ..(2)
Solving Eqn(1) & Eqn(2), we will get
A = 70 and B = 30
Naresh's age = 70 years and Abdul's age = 30 years.

Question 6 |

The ages of Smirthi and Samantha vary by 16 years, Six years ago, Deepika’s age was three times as that of Smirthi’s, find their current ages.

A | 11 years, 28 years |

B | 10 years, 28 years |

C | 16 years, 34 years |

D | 14 years, 30 years |

Question 6 Explanation:

Let Smirthi's age = A years
So, Deepika's age = (A + 16) years
Also, 3(A - 6) = A + 16 - 6 or, A = 14
Smirthi's age = 14 years
and, Deepika's age = 14 + 16
= 30 years

Question 7 |

A father is Quadrice as old as his daughter today. After 20 years, he would be only two times as old. At the time of daughter's birth, how much old the father be?

A | 30 |

B | 31 |

C | 37 |

D | 35 |

Question 7 Explanation:

If the ages of daughter and father today by 'A' and '4A' years correspondingly.
4A + 20 = 2 (A+20)
A = 10 years => 4A = 40 years.
At the time of daughter's birth, father's Age
40 - 10 = 30 years old

Question 8 |

Right now, the ratio between the ages of Karthikh and Prasath is 4:3. After 6 years, Karthikh’s age will be 26 years. What is the age of Prasath right now?

A | 15 |

B | 19 |

C | 25 |

D | 21 |

Question 8 Explanation:

If the current ages of Karthikh and Prasath be 4A years and 3A years correspondingly.
Then, 4A + 6 = 26
4A = 20
A = 5
Prasath's age = 3A = 15 years.

Question 9 |

Sachin is 40 years old and Vijay is 60 years old. How many decades ago was the proportion of their ages 3 : 5?

A | 10 |

B | 37 |

C | 27 |

D | 20 |

Question 9 Explanation:

If the ratio was 3 : 5, 'A' years ago.
Then, 7A - 6A = 4
A = 4
Then, {( 40 - A)/(60 - A)}= (3/5)
5 (40 - A) = 3(60 - A)
2A = 20
A = 10
{Ans in decades : 1 }

Question 10 |

The current ages of 3 individuals are in the ratio 4:7:9. 0.8 decades ago, the sum of their ages was 56. Find their current ages in years. [0.8 Decades = 8years]

A | 16, 28, 36 |

B | 20, 32, 46 |

C | None of these |

D | 18, 30, 38 |

Question 10 Explanation:

Let their current ages are 4A, 7A and 9A years correspondingly.
Then, (4A - 8) + (7A - 8) + (9A - 8) = 56
20A = 80
A = 4
Their current ages are
16 years, 28 years and 36 years correspondingly.

Question 11 |

The ratio between the current age of A and B is 6:7. If B is 4 years old than A. What will be the ratio of the ages of A and B after 4 years?

A | None of these |

B | 4:5 |

C | 4:3 |

D | 3 : 1 |

E | Data inadequate |

Question 11 Explanation:

If A's age and B's age will be 6A years and 7A years correspondingly
Then, 7A - 6A = 4
A = 4
Needed ratio = (6A + 4) : (7A + 4)
= 28 : 32
= 7 : 8

Question 12 |

0.2 decades ago a person was 6 times as old as his daughter, After 18 years, he will be two times as old as his daughter. Then their current ages are,
[0.2 decades = 2 years]

A | None of these |

B | 7 years |

C | 11 years |

D | 9 years |

Question 12 Explanation:

None of these

Question 13 |

A person's age is 125% of what it was one decade ago, but 83(1/3)% of what it will be after one decade. What is his current age? [1 decade = 10 years]

A | 35 years |

B | 55 years |

C | 40 years |

D | 50 years |

Question 13 Explanation:

Let, current age is A years.
Then, 125% of (A - 10) = A
and, 83(1/3)% of (A + 10) = A
Therefore 125% of (A-10) = 83(1/3)% of (A+10)
or, (5/4) (A - 10) =(5/6)(A+10)
or, (5/4)A -(5/6)A = (50/6)+(50/4)
or, (5A/12)= (250/12) or,
A=50 years.

Question 14 |

Amith was 3 times as old as Harsh 6 years back. Amith will be 5/3 times as old as Harsh 6 years hence. How much old is Harsh today?

A | 12 |

B | 11 |

C | 22 |

D | 21 |

Question 14 Explanation:

Let Harsh's age 6 years back = A
Then, Amith's age 6 years back = 32.
Then 5/3 (A + 6 + 6) = (3A + 6 + 6)
5(A + 12) = 3 (3A + 12)
4A = 24
A = 6
Harsh's age today = (A + 6) years
= 12 years

Question 15 |

Current ages of Rahim and Thomas are in the ratio of 5 : 4 correspondingly. 0.3 decades hence, the ratio of their ages will become 11 : 9 correspondingly, What is Thomas’s current age in years? [0.3 decades : 3 years]

A | 24 |

B | 42 |

C | 14 |

D | None of these |

Question 15 Explanation:

If current ages of Rahim and Thomas be 5A years and 4A years correspondingly
Then, 5A + 3 = 11
4A + 3 = 9
9(5A + 3)=11(4A + 3)
A = 6
Thomas's current age = 4A
= 24 years.

Question 16 |

One decade ago, X was half of Y in age. If the proportion of their current ages is 3:4, what will be the overall of their current ages?

A | 20 |

B | 10 |

C | None of thse |

D | 25 |

Question 16 Explanation:

Let the ages of X and Y 1 decade ago be A and 2A years correspondingly.
Then, [ (A +10)/2A+10) ] = (3/4)
4 (A - 10) = 3(2A - 10)
2A = 10
A = 5
Therefore,
Sum of theircurrent ages = (A + 10) + (2A + 10) = (3A + 20)
= 35 years

Question 17 |

1 Decade ago, Karthikh’s mother was quadrice older than her son. After one decade, the mother will be two times older than her son. The current age of Karthikh is?
[Decade = 10 Years; quadrice= 4 times]

A | 12 years |

B | 23 years |

C | 8 years |

D | 20 years |

Question 17 Explanation:

Let Karthikh's age 10 years ago be A year
His mother's age 1 decade ago = 4A
(4A + 10) + 10 = 2 (A + 10 +10)
2A = 20 or A =10
Current age of Karthikh = (A + 10)
= 20 years

Question 18 |

A father is two times as old as his daughter. 2 decades ago, the age of the father was 12 times the age of the daughter. The current age of the father is
[ 2 Decades : 20 years]

A | 32 |

B | 22 |

C | 44 |

D | 45 |

Question 18 Explanation:

Let daughter's age = A.
Then father's age = 2A
12 (A - 20) = (2A - 20)
10A = 220
A = 22
Father's current age = 44 years.

Question 19 |

15 years hence, Karthikh will be just Quadrice as old as he was 15 years ago, How old is Karthikh at now? [ Quadrice = 4 Times ]

A | 20 |

B | 35 |

C | 25 |

D | 30 |

Question 19 Explanation:

Let the current age of Karthikh is A years
Then, A+15 = 4(A – 15)
Therefore A = 25

Question 20 |

The Avg age of a class of 22 subject areas in 21 years. The avg increased by one when the lecturer’s age also involved. What is the age of the Lecturer?

A | 40 |

B | 41 |

C | 43 |

D | 44 |

Question 20 Explanation:

Average * Subject Areas = Total Age
So => 21 years x 22 numbers = 462 years ... (1)
=> 22 years x 23 numbers = 506 years ... (2)
Therefore Lecturer’s age = Eqn(2) - Eqn(1)
= 506 – 462
= 44 Years.

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